E Exercises

Andromaque Jean-Louis problem 9.54 Faced with rising fax costs, a substantial issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead. Exceptions are allowed, but they dower the average to be 10 or below. The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample tight of 14.44 with a standard deviation of 4.45 pages. (a) At the .01 aim of significance, is the true misbegot great than 10? (b) consumption Excel to go the right-tail p-value. a) At the .01 level of significance, is the true mean greater than 10? The critical value for one-tail essay with alpha is equal to 1 % which df=34 which is equal to 2.32634 The test statistic is z(14.44) which translates to (14.44-10)/[4.45/? (35)] equals 5.9028 Ha: ? > 10 Ho: ? = 10 The test statistics is in the spurned interval of Ho. thither is enough evidence supporting the seize the true mean is greater than 10. b) Use Excel to find the right-tail p-value? p-value = P(5.9028 < t < 10) = 0.00000057579... = 1 NORMSDIST(5.9027) Problem 9.56 A take was flipped 60 times and came up heads 38 times. (a) At the .

10 level of significance, is the coin bias toward heads? Show your finale rule and calculations. (b) manoeuvre a p-value and interpret it. a) At the .10 level of significance, is the coin bleached toward heads? Show your decision rule and calculations. Ha: p> 0.5 Ho: p< 0.5 ? = np = (60)(0.5) = 30 ? = ?npq = ?(0.5)(0.5)(60) = 3.8730 (38 - 30) / 3.8730 = 2.0656 As the test statistic is great er than critical value, Reject Ho The test! reflects that the coin is biased toward heads. b) Calculate a p-value and interpret it. p(z > 2.0656) = 0.0194 The Null possibleness is rejected and the claim is supported.If you want to get a wide essay, company it on our website: OrderCustomPaper.com

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